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MHT CET 2026 (15 Apr, Shift 2) · Pressure & Kinetic Energy of a Gas

Pressure & Kinetic Energy of a Gas question from MHT CET 2026 (15 Apr, Shift 2)

Q7MHT CET 2026 · 15 APR · SHIFT 2Difficult

Pressure & Kinetic Energy of a Gas

The average translational kinetic energy of a molecule in a gas is $E_1$ . The kinetic energy of the electron (e) accelerated from rest through potential difference 'V' volt is $E_2$ . The temperature at which $E_1 = E_2$ possible is (N = number of molecules, R = gas constant)

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Answer: (b)

$E_1 = \frac{3}{2}k_BT = \frac{3}{2}\frac{R}{N}T$ and $E_2 = eV$ .
$E_1 = E_2 \Rightarrow T = \frac{2eVN}{3R}$
So the answer is (b) $\frac{2eVN}{3R}$ .

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