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JEE Main 2021 (1 Sep, Shift 2) · Pressure & Kinetic Energy of a Gas

Pressure & Kinetic Energy of a Gas question from JEE Main 2021 (1 Sep, Shift 2)

Q34JEE Main 2021 · 1 SEP · SHIFT 2Medium

Pressure & Kinetic Energy of a Gas

The average translational kinetic energy of N2 gas molecules at .............∘{}^\circC becomes equal to the K.E. of an electron accelerated from rest through a potential difference of 0.1 volt. (Given kB = 1.38 ×\times 10−-23 J/K) (Fill the nearest integer).

Numerical answer type. Work it out, then open the answer.

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Answer: 500

  1. 32kBT=eV=0.1×1.6×10−19=1.6×10−20\frac{3}{2}k_BT = eV = 0.1 \times 1.6 \times 10^{-19} = 1.6 \times 10^{-20} J
  2. T=2×1.6×10−203×1.38×10−23≈773T = \frac{2 \times 1.6 \times 10^{-20}}{3 \times 1.38 \times 10^{-23}} \approx 773 K
  3. 773−273=500∘773 - 273 = 500^\circC
  4. So the answer is 500∘500^\circC.
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