The binding energy of deuteron is 2.2 MeV and that of ⁴₂ He is 28 MeV. If two deuterons are fused to form one ⁴₂ He then the energy released is (a) 30.2 MeV (b) 25.8 MeV (c) 23.6 MeV (d) 19.2 MeV

Answer: (c). Q = BE(⁴He) - 2 BE(²H). Q = 28 - 2×2.2 = 23.6 MeV. So the answer is (c) 23.6 MeV.

The binding energy of deuteron is 2.2 MeV and that of ⁴₂ He is 28… | NEET 2006 (AIPMT)

Q30NEET 2006 · AIPMTEasy

Nuclear Fission & Fusion

The binding energy of deuteron is 2.2 MeV and that of ${}^{4}_{2}$ He is 28 MeV. If two deuterons are fused to form one ${}^{4}_{2}$ He then the energy released is

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Answer: (c)

$Q = \text{BE}({}^4\text{He}) - 2\,\text{BE}({}^2\text{H})$ .
$Q = 28 - 2\times2.2 = 23.6\text{ MeV}$ .
So the answer is (c) $23.6\text{ MeV}$ .

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