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NEET 2000 (AIPMT) · Simple Pendulum

Simple Pendulum question from NEET 2000 (AIPMT)

Q85NEET 2000 · AIPMTEasy

Simple Pendulum

The bob of simple pendulum having length ll, is displaced from mean position to an angular position q with respect to vertical. If it is released, then velocity of bob at equilibrium position

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Answer: (a)

  1. The bob falls through height h=l−lcos⁡θ=l(1−cos⁡θ)h = l - l\cos\theta = l(1 - \cos\theta) (q in the question means θ\theta).
  2. Energy conservation: 12mv2=mgh\frac{1}{2}mv^2 = mgh.
  3. v=2gl(1−cos⁡θ)v = \sqrt{2gl(1 - \cos\theta)}
  4. So the answer is (a).
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