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MHT CET 2023 (13 May, Shift 2) · Logic Gates

Logic Gates question from MHT CET 2023 (13 May, Shift 2)

Q89MHT CET 2023 · 13 MAY · SHIFT 2Medium

Logic Gates

The Boolean expression for the following combination is

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Answer: (c)

Upper AND gets $\bar{A}$ and $B$ : output $\bar{A} \cdot B$ .
Lower AND gets $A$ and $\bar{B}$ : output $A \cdot \bar{B}$ .
OR gate: $Y = (\bar{A} \cdot B) + (A \cdot \bar{B})$ (XOR).
So the answer is (c).

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