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MHT CET 2024 (16 May, Shift 2) · Logic Gates

Logic Gates question from MHT CET 2024 (16 May, Shift 2)

Q60MHT CET 2024 · 16 MAY · SHIFT 2Medium

Logic Gates

The Boolean expression for the given combination of logic gates is

Figure

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Answer: (c)

  1. NOT gate gives Aˉ\bar{A}; AND gate gives B⋅CB \cdot C.
  2. OR gate: Y=Aˉ+(B⋅C)Y = \bar{A} + (B \cdot C).
  3. So the answer is (c).
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