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MHT CET 2024 (3 May, Shift 2) · Logic Gates

Logic Gates question from MHT CET 2024 (3 May, Shift 2)

Q56MHT CET 2024 · 3 MAY · SHIFT 2Easy

Logic Gates

The Boolean expression for 'X-OR' gate $C = (A \oplus B)$ is equal to

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Answer: (d)

XOR is 1 only when the inputs differ: $A = 0, B = 1$ or $A = 1, B = 0$ .
These two cases are $\overline{A} \cdot B$ and $A \cdot \overline{B}$ .
$A \oplus B = \overline{A} \cdot B + A \cdot \overline{B}$ .
So the answer is (d).

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