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JEE Main 2022 (24 Jun, Shift 1) · Bulk Modulus & Compressibility

Bulk Modulus & Compressibility question from JEE Main 2022 (24 Jun, Shift 1)

Q11JEE Main 2022 · 24 JUN · SHIFT 1Easy

Bulk Modulus & Compressibility

The bulk modulus of a liquid is 3 ×\times 1010 Nm−2. The pressure required to reduce the volume of liquid by 2% is:

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Answer: (c)

  1. ΔP=BΔVV\Delta P = B\dfrac{\Delta V}{V}
  2. ΔP=3×1010×0.02=6×108 N m−2\Delta P = 3 \times 10^{10} \times 0.02 = 6 \times 10^8\text{ N m}^{-2}
  3. So the answer is (c) 6×108 N m−26 \times 10^8\text{ N m}^{-2}.
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