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MHT CET 2026 (13 Apr, Shift 1) · Dielectrics

Dielectrics question from MHT CET 2026 (13 Apr, Shift 1)

Q16MHT CET 2026 · 13 APR · SHIFT 1Medium

Dielectrics

The capacitance of a capacitor becomes 76\frac{7}{6} times the original value if dielectric slab of thickness t=2d3t = \frac{2d}{3} is introduced between the plates, where 'd' is the distance of separation between the plates. The dielectric constant of the slab is

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Answer: (b)

  1. C′C=dd−t+tK=76\frac{C'}{C}=\frac{d}{d-t+\frac{t}{K}}=\frac{7}{6} with t=2d3t=\frac{2d}{3}.
  2. 13+23K=67⇒23K=1121\frac{1}{3}+\frac{2}{3K}=\frac{6}{7} \Rightarrow \frac{2}{3K}=\frac{11}{21}
  3. K=4233=1411K=\frac{42}{33}=\frac{14}{11}
  4. So the answer is (b) 1411\frac{14}{11}.
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