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MHT CET 2023 (10 May, Shift 2) · Pure R, L and C Circuits

Pure R, L and C Circuits question from MHT CET 2023 (10 May, Shift 2)

Q38MHT CET 2023 · 10 MAY · SHIFT 2Easy

Pure R, L and C Circuits

The capacitive reactance of a capacitor ' $C$ ' is $X\ \Omega$ . Both, the frequency of a.c. supply and capacitance of the above capacitor are doubled. The new capacitive reactance will be

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Answer: (a)

$X_C = \frac{1}{2\pi f C} \propto \frac{1}{fC}$
Both $f$ and $C$ doubled: $X' = \frac{X}{4}$
So the answer is (a) $\frac{X}{4}\ \Omega$ .

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