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MHT CET 2025 (26 Apr, Shift 1) · Dielectrics

Dielectrics question from MHT CET 2025 (26 Apr, Shift 1)

Q28MHT CET 2025 · 26 APR · SHIFT 1Easy

Dielectrics

The capacity of air filled parallel plate capacitor is C0C_0. One-half of the space between the plates is filled with a dielectric constant ' K ' as shown in figure. The new capacity becomes CnC_n. The ratio CnC_n to C0C_0 is

Figure

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Answer: (a)

  1. The dielectric fills half the plate area across the full gap, so the two halves are in parallel.
  2. Each half alone has capacitance C02\frac{C_0}{2}; the dielectric half becomes KC02\frac{KC_0}{2}.
  3. Cn=KC02+C02=(K+1)C02C_n = \frac{KC_0}{2} + \frac{C_0}{2} = \frac{(K+1)C_0}{2}.
  4. So CnC0=K+12\frac{C_n}{C_0} = \frac{K+1}{2}, answer (a).
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