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JEE Main 2005 (AIEEE) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2005 (AIEEE)

Q127JEE Main 2005 · AIEEEMedium

Acceleration Due to Gravity

The change in the value of gg at a height hh above the surface of the earth is the same as at a depth dd below the surface of earth. When both dd and hh are much smaller than the radius of earth, then which one of the following is correct?

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Answer: (d)

  1. Change at height: Δg=2ghR\Delta g = \frac{2gh}{R} (for h≪Rh \ll R)
  2. Change at depth: Δg=gdR\Delta g = \frac{gd}{R}
  3. 2ghR=gdR⇒d=2h\frac{2gh}{R} = \frac{gd}{R} \Rightarrow d = 2h
  4. So the answer is (d).
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