The circuit diagram of potentiometer used to measure the internal… | JEE Main 2022 (30 Jun, Shift 1)

Q52JEE Main 2022 · 30 JUN · SHIFT 1Medium

Potentiometer

The circuit diagram of potentiometer used to measure the internal resistance of a cell (E) is shown in figure. The key 'K' is kept closed so as to send constant current through potentiometer wire. When key 'K1' is kept open the null point is found to be at 120 cm on the potentiometer wire. When the key 'K1' is closed the null point is shifted at 80 cm at the potentiometer wire. The internal resistance of the given cell is _____________ $\Omega$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 2

$K_1$ open: open-circuit length $l_0 = 120$ cm. $K_1$ closed: cell shunted by $R = 4\ \Omega$ , $l = 80$ cm.
$r = R\dfrac{l_0-l}{l} = 4\times\dfrac{120-80}{80}$
$r = 2\ \Omega$

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