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JEE Main 2022 (30 Jun, Shift 1) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2022 (30 Jun, Shift 1)

Q55JEE Main 2022 · 30 JUN · SHIFT 1Medium

Special Purpose Diodes

The circuit diagram used to study the characteristic curve of a zener diode is connected to variable power supply (0 −- 15 V) as shown in figure. A zener diode with maximum potential Vz = 10 V and maximum power dissipation of 0.4 W is connected across a potential divider arrangement. The value of resistance RP connected in series with the zener diode to protect it from the damage is ________________ Ω\Omega.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 125

  1. Maximum Zener current: I=PVZ=0.410=0.04I = \frac{P}{V_Z} = \frac{0.4}{10} = 0.04 A
  2. At the full supply 1515 V, drop across RPR_P is 15−10=515 - 10 = 5 V.
  3. RP=50.04=125 ΩR_P = \frac{5}{0.04} = 125\ \Omega
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