P-N Junction Diode question from JEE Main 2006 (AIEEE)

Answer: (b)

1. Current leaves the battery through $4\ \Omega$ and tries to go down both branches.
2. $D_1$ points upward, so it is reverse biased (open); $D_2$ points downward, so it conducts (ideal, zero resistance).
3. Total resistance $= 4 + 2 = 6\ \Omega$
4. $I = \dfrac{12}{6} = 2\text{ A}$, so the answer is (b) $2.00\text{ A}$.