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JEE Main 2020 (9 Jan, Shift 2) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2020 (9 Jan, Shift 2)

Q77JEE Main 2020 · 9 JAN · SHIFT 2Difficult

Special Purpose Diodes

The circuit shown below is working as a 8 V dc regulated voltage source. When 12 V is used as input, the power dissipated (in mW) in each diode is; (considering both zener diodes are identical) _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 40

The two identical Zeners in series hold $V_0 = 8$ V, so each has $4$ V across it.
Drop across the two resistors: $12 - 8 = 4$ V, total resistance $400\,\Omega$ .
$I = \dfrac{4}{400} = 10$ mA (no load current drawn).
Power in each diode: $P = 4 \times 10\times10^{-3} = 40$ mW

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