The circuit shown contains two ideal diodes D₁ and D₂. If a cell of… | MHT CET 2026 (12 May, Shift 2)

Q12MHT CET 2026 · 12 MAY · SHIFT 2Medium

P-N Junction Diode

The circuit shown contains two ideal diodes $D_1$ and $D_2$ . If a cell of e.m.f. $3$ V and negligible internal resistance is connected, then the current through $70\ \Omega$ resistance in ampere is

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Answer: (c)

The left plate of the cell is positive, so current reaches the left junction and moves right through the diode branches.
$D_1$ points left (reverse biased): no current. $D_2$ points right (forward biased): conducts.
Circuit: $30\ \Omega$ (with $D_2$ ) in series with $70\ \Omega$ .
$I = \dfrac{3}{30 + 70} = 0.03$ A
So the answer is (c) $0.03$ A.

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P-N Junction Diode question from MHT CET 2026 (12 May, Shift 2)

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