The circuit shown here has two batteries of 8.0 V and 16.0 V and three resistors 3 Ω, 9 Ω and 9 Ω and a capacitor 5.0 μ F. How much is the current I in the circuit in steady state? (a) 1.6 A (b) 0.67 A (c) 2.5 A (d) 0.25 A

Answer: (b). Steady state: the capacitor branch (with its 9 Ω) carries no current. Outer loop: 8 V cell with 3 Ω and 16 V cell with 9 Ω; the cells oppose each other in this loop. I = (16-8)/(3+9) = 8/12 = 0.67 A So the answer is (b) 0.67 A.

The circuit shown here has two batteries of 8.0 V and 16.0 V and… | JEE Main 2014 (12 Apr, Shift 1)

Q40JEE Main 2014 · 12 APR · SHIFT 1Medium

Capacitors in DC Circuits & RC

The circuit shown here has two batteries of 8.0 V and 16.0 V and three resistors 3 $\Omega$ , 9 $\Omega$ and 9 $\Omega$ and a capacitor 5.0 $\mu$ F.

How much is the current I in the circuit in steady state?

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Answer: (b)

Steady state: the capacitor branch (with its $9\ \Omega$ ) carries no current.
Outer loop: 8 V cell with $3\ \Omega$ and 16 V cell with $9\ \Omega$ ; the cells oppose each other in this loop.
$I = \dfrac{16-8}{3+9} = \dfrac{8}{12} = 0.67\text{ A}$
So the answer is (b) 0.67 A.

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Capacitors in DC Circuits & RC question from JEE Main 2014 (12 Apr, Shift 1)

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