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JEE Main 2003 (AIEEE) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from JEE Main 2003 (AIEEE)

Q46JEE Main 2003 · AIEEEEasy

Velocity, Acceleration & Variable Motion

The co-ordinates of a moving particle at any time 't' are given by x = $\alpha$ t3 and y = βt3. The speed of the particle at time 't' is given by

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Answer: (b)

$v_x = \dfrac{dx}{dt} = 3\alpha t^2$ , $v_y = \dfrac{dy}{dt} = 3\beta t^2$
Speed $= \sqrt{v_x^2 + v_y^2} = 3t^2\sqrt{\alpha^2 + \beta^2}$
So the answer is (b) $3t^2\sqrt{\alpha^2 + \beta^2}$ .

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