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MHT CET 2024 (16 May, Shift 1) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from MHT CET 2024 (16 May, Shift 1)

Q10MHT CET 2024 · 16 MAY · SHIFT 1Medium

Velocity, Acceleration & Variable Motion

The co-ordinates of a moving particle at any time ' tt ' are given by x=αt3x = \alpha t^3 and y=βt3y = \beta t^3 where α\alpha and β\beta are constants. The speed of the particle at time ' tt ' is given by

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Answer: (d)

  1. vx=3αt2v_x = 3\alpha t^2, vy=3βt2v_y = 3\beta t^2
  2. Speed =vx2+vy2=3t2α2+β2= \sqrt{v_x^2 + v_y^2} = 3t^2\sqrt{\alpha^2 + \beta^2}
  3. So the answer is (d).
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