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MHT CET 2026 (15 Apr, Shift 1) · Mutual Inductance

Mutual Inductance question from MHT CET 2026 (15 Apr, Shift 1)

Q5MHT CET 2026 · 15 APR · SHIFT 1Easy

Mutual Inductance

The coefficient of mutual induction is 33H and induced e.m.f. across secondary is 44 kV. Current in primary is reduced from 77A to 22A. The time required for the change of current is

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Answer: (a)

  1. e=MΔIΔt⇒Δt=M ΔIee = M\dfrac{\Delta I}{\Delta t} \Rightarrow \Delta t = \dfrac{M\,\Delta I}{e}
  2. Δt=3×54000=3.75×10−3\Delta t = \dfrac{3 \times 5}{4000} = 3.75\times 10^{-3} s
  3. So the answer is (a).
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