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JEE Main 2021 (24 Feb, Shift 1) · Friction Basics

Friction Basics question from JEE Main 2021 (24 Feb, Shift 1)

Q15JEE Main 2021 · 24 FEB · SHIFT 1Easy

Friction Basics

The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be _________ N. [g = 10 ms ${}^{-}$ 2]

Numerical answer type. Work it out, then open the answer.

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Answer: 25

Normal force $N = F$ (horizontal push); friction must hold the weight: $\mu F \ge mg$ .
$F = \dfrac{mg}{\mu} = \dfrac{0.5 \times 10}{0.2}$
$F = 25$ N

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