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JEE Main 2021 (26 Aug, Shift 2) · Two-Body Friction

Two-Body Friction question from JEE Main 2021 (26 Aug, Shift 2)

Q5JEE Main 2021 · 26 AUG · SHIFT 2Medium

Two-Body Friction

The coefficient of static friction between two blocks is 0.5 and the table is smooth. The maximum horizontal force that can be applied to move the blocks together is .................. N. (take g = 10 ms-2)

Numerical answer type. Work it out, then open the answer.

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Answer: 15

F acts on the 2 kg block; the 1 kg block moves only through friction: $a_{max} = \mu g = 0.5 \times 10 = 5$ m/s $^2$ .
$F_{max} = (1 + 2) \times 5$
$F_{max} = 15$ N

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