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NEET 2004 (AIPMT) · Friction Basics

Friction Basics question from NEET 2004 (AIPMT)

Q33NEET 2004 · AIPMTEasy

Friction Basics

The coefficient of static friction, $\mu$ s, between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. (g = 10 m/s2)

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Answer: (d)

For no motion, the weight of B must not exceed the limiting friction on A: $m_B g \le \mu_s m_A g$ .
$m_B = \mu_s m_A = 0.2 \times 2$
$m_B = 0.4$ kg, so the answer is (d).

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