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MHT CET 2026 (14 May, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2026 (14 May, Shift 1)

Q5MHT CET 2026 · 14 MAY · SHIFT 1Medium

Thermometry & Thermal Expansion

The coefficient of volume expansion of mercury is 18×10−5/∘18 \times 10^{-5}/^\circC. A thermometer bulb has volume 10−610^{-6} m3^3 and cross-section of stem is 0.0040.004 cm2^2. Assuming bulb is filled with mercury at 0∘0^\circC then the mercury column at 100∘100^\circC is

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Answer: (d)

  1. Rise in mercury volume (bulb expansion neglected): ΔV=VγΔT=10−6×18×10−5×100=1.8×10−8\Delta V=V\gamma\Delta T=10^{-6}\times18\times10^{-5}\times100=1.8\times10^{-8} m3^3
  2. Stem area A=0.004A=0.004 cm2=4×10−7^2=4\times10^{-7} m2^2
  3. l=ΔVA=1.8×10−84×10−7=0.045l=\frac{\Delta V}{A}=\frac{1.8\times10^{-8}}{4\times10^{-7}}=0.045 m
  4. So the answer is (d) 4.54.5 cm.
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