Physics Circle home Student Login

Home›Chapters›Magnetic Properties of Materials PYQs›Hysteresis, Soft Iron vs Steel & Shielding›Question 17

JEE Main 2014 · Hysteresis, Soft Iron vs Steel & Shielding

Hysteresis, Soft Iron vs Steel & Shielding question from JEE Main 2014

Q17JEE Main 2014Easy

Hysteresis, Soft Iron vs Steel & Shielding

The coercivity of a small magnet where the ferromagnet gets demagnetized is 3×103 Am−1.3 \times 10^{3}\text{ Am}^{-1}. The current required to be passed in a solenoid of length 10 cm10\text{ cm} and number of turns 100,100, so that the magnet gets demagnetized when inside the solenoid, is:

Show answer and solution

Answer: (c)

  1. The solenoid's H=nIH = nI must equal the coercivity: I=HnI = \dfrac{H}{n}.
  2. n=NL=1000.1=1000 m−1n = \dfrac{N}{L} = \dfrac{100}{0.1} = 1000\text{ m}^{-1}
  3. I=3×1031000=3 AI = \dfrac{3 \times 10^{3}}{1000} = 3\text{ A}
  4. So the answer is (c) 3 A.
Report a mistake

More questions on Hysteresis, Soft Iron vs Steel & Shielding