The coil of area 0.1 m ² has 1000 turns. It is placed in a magnetic field of strength 5 × 10⁻⁴ T. The average e.m.f. induced in the coil, if rotated through 180° in 0.1 s is ( cos 0° = 1, cos 180° = -1) (a) 0 V (b) 2.5 V (c) 1 V (d) 5 V

Answer: (c). Rotating through 180°: flux goes from NBA to -NBA, so |Δφ| = 2NBA. 2NBA = 2 × 1000 × 5 × 10⁻⁴ × 0.1 = 0.1 Wb e = (Δφ)/(Δ t) = (0.1)/(0.1) = 1 V So the answer is (c) 1 V.

The coil of area 0.1 m ² has 1000 turns. It is placed in a magnetic… | MHT CET 2026 (12 May, Shift 2)

Q12MHT CET 2026 · 12 MAY · SHIFT 2Medium

Magnetic Flux & Faraday's Law

The coil of area $0.1$ m $^{2}$ has $1000$ turns. It is placed in a magnetic field of strength $5 \times 10^{-4}$ T. The average e.m.f. induced in the coil, if rotated through $180^\circ$ in $0.1$ s is ( $\cos 0^\circ = 1, \cos 180^\circ = -1$ )

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Answer: (c)

Rotating through $180^\circ$ : flux goes from $NBA$ to $-NBA$ , so $|\Delta\phi| = 2NBA$ .
$2NBA = 2 \times 1000 \times 5 \times 10^{-4} \times 0.1 = 0.1$ Wb
$e = \frac{\Delta\phi}{\Delta t} = \frac{0.1}{0.1} = 1$ V
So the answer is (c) 1 V.

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Magnetic Flux & Faraday's Law question from MHT CET 2026 (12 May, Shift 2)

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