Physics Circle home Student Login

Home›Chapters›Semiconductor Electronics PYQs›Junction Transistor›Question 55

NEET 2022 (Phase 2) · Junction Transistor

Junction Transistor question from NEET 2022 (Phase 2)

Q55NEET 2022 · PHASE 2Medium

Junction Transistor

The collector current in a common base amplifier using n-p-n transistor is 24 mA. If 80% of the electrons released by the emitter is accepted by the collector, then the base current is numerically:

Show answer and solution

Answer: (d)

  1. IC=0.8 IE⇒IE=240.8=30I_C = 0.8\,I_E \Rightarrow I_E = \dfrac{24}{0.8} = 30 mA.
  2. IB=IE−IC=30−24=6I_B = I_E - I_C = 30 - 24 = 6 mA.
  3. In n-p-n, conventional current enters at the base and collector and leaves at the emitter, so IBI_B enters the base.
  4. So the answer is (d) 6 mA and entering the base.
Report a mistake

More questions on Junction Transistor