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JEE Main 2021 (27 Aug, Shift 2) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2021 (27 Aug, Shift 2)

Q33JEE Main 2021 · 27 AUG · SHIFT 2Easy

Ohm's Law, Resistivity & Temperature

The Colour coding on a carbon resistor is shown in the given figure. The resistance value of the given resistor is:

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Answer: (d)

Violet = 7, Green = 5, Red = multiplier $10^2$ , Gold = $\pm 5\%$ .
$R = 75 \times 100 = 7500\ \Omega$
Tolerance $= 5\%$ of $7500 = 375\ \Omega$
So the answer is (d) $(7500 \pm 375)\ \Omega$ .

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