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MHT CET 2020 (19 Oct, Shift 2) · Bulk Modulus & Compressibility

Bulk Modulus & Compressibility question from MHT CET 2020 (19 Oct, Shift 2)

Q15MHT CET 2020 · 19 OCT · SHIFT 2Easy

Bulk Modulus & Compressibility

The compressibility of water is 5×10−10 m2/N5 \times 10^{-10}\text{ m}^2\text{/N}. Pressure of 15×106 Pa15 \times 10^{6}\text{ Pa} is applied on 100 mL volume of water. The change in the volume of water is

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Answer: (b)

  1. ΔV=kPV\Delta V = kPV, where kk is compressibility; pressure reduces the volume.
  2. ΔV=5×10−10×15×106×100 mL=0.75 mL\Delta V = 5 \times 10^{-10} \times 15 \times 10^6 \times 100\text{ mL} = 0.75\text{ mL}
  3. So the answer is (b) 0.75 mL decrease.
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