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MHT CET 2024 (9 May, Shift 2) · Magnetisation: B, H, M, χ & μ

Magnetisation: B, H, M, χ & μ question from MHT CET 2024 (9 May, Shift 2)

Q23MHT CET 2024 · 9 MAY · SHIFT 2Easy

Magnetisation: B, H, M, χ & μ

The correct relation between total magnetic field (B)(B), magnetic intensity (H)(H), permeability of free space (μ0)(\mu_0) and susceptibility (χ)(\chi) is

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Answer: (c)

  1. B=μ0(H+M)B = \mu_0(H + M) with M=χHM = \chi H.
  2. B=μ0H(1+χ)⇒BH=μ0(1+χ)B = \mu_0 H(1+\chi) \Rightarrow \dfrac{B}{H} = \mu_0(1+\chi)
  3. So the answer is (c).
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