The correct relationship between the two current gains α and β in a transistor is (a) α = (β)/(1 + β) (b) α = (1 + β)/(β) (c) β = (α)/(1 + α) (d) β = (α)/(α - 1)

Answer: (a). IE = IB + IC; divide by IC: (1)/(α) = (1)/(β) + 1 = (1+β)/(β) α = (β)/(1+β) So the answer is (a).

The correct relationship between the two current gains α and β in a… | NEET 1997 (AIPMT)

Q126NEET 1997 · AIPMTEasy

Junction Transistor

The correct relationship between the two current gains $\alpha$ and $\beta$ in a transistor is

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Answer: (a)

$I_E = I_B + I_C$ ; divide by $I_C$ : $\frac{1}{\alpha} = \frac{1}{\beta} + 1 = \frac{1+\beta}{\beta}$
$\alpha = \frac{\beta}{1+\beta}$
So the answer is (a).