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JEE Main 2023 (11 Apr, Shift 1) · Total Internal Reflection

Total Internal Reflection question from JEE Main 2023 (11 Apr, Shift 1)

Q21JEE Main 2023 · 11 APR · SHIFT 1Easy

Total Internal Reflection

The critical angle for a denser-rarer interface is 45∘45^\circ. The speed of light in rarer medium is 3×108 m/s3 \times 10^{8}\text{ m/s}. The speed of light in the denser medium is:

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Answer: (a)

  1. sin⁡C=μrμd=vdvr\sin C = \frac{\mu_r}{\mu_d} = \frac{v_d}{v_r}.
  2. vd=vrsin⁡45∘=3×1082=2.12×108 m/sv_d = v_r\sin 45^\circ = \frac{3 \times 10^8}{\sqrt{2}} = 2.12 \times 10^8\text{ m/s}
  3. So the answer is (a) 2.12×108 m/s2.12 \times 10^8\text{ m/s}.
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