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JEE Main 2020 (8 Jan, Shift 1) · Total Internal Reflection

Total Internal Reflection question from JEE Main 2020 (8 Jan, Shift 1)

Q38JEE Main 2020 · 8 JAN · SHIFT 1Medium

Total Internal Reflection

The critical angle of a medium for a specific wavelength, if the medium has relative permittivity 3 and relative permeability $\frac{4}{3}$ for this wavelength, will be:

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Answer: (c)

$n = \sqrt{\varepsilon_r \mu_r} = \sqrt{3\times\frac{4}{3}} = 2$ .
$\sin C = \frac{1}{n} = \frac{1}{2} \Rightarrow C = 30^\circ$ .
So the answer is (c) $30^\circ$ .

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