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MHT CET 2026 (20 May, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (20 May, Shift 1)

Q1MHT CET 2026 · 20 MAY · SHIFT 1Easy

Self-Inductance & Energy

The current flowing through an inductor of self-inductance L is continuously increasing at constant rate. The variation of induced e.m.f. (e) versus time tt is shown graphically by

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Answer: (d)

  1. Self-induced emf: e=−LdIdte = -L\frac{dI}{dt}.
  2. dIdt\frac{dI}{dt} is a positive constant, so ee is a constant negative value at all times.
  3. The graph is a horizontal line below the time axis.
  4. So the answer is (d).
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