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MHT CET 2025 (20 Apr, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2025 (20 Apr, Shift 1)

Q24MHT CET 2025 · 20 APR · SHIFT 1Easy

Self-Inductance & Energy

The current flowing through an inductor of selfinductance L is continuously increasing at constant rate. The variation of induced e.m.f. (e) verses dI/dtdI/dt is shown graphically by figure

Figure

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Answer: (b)

  1. e=−LdIdte = -L\frac{dI}{dt}: ee is directly proportional to dIdt\frac{dI}{dt} with a negative constant −L-L.
  2. The graph must be a straight line through the origin going into negative ee.
  3. That is graph (B), which is option (a).
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