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MHT CET 2026 (13 Apr, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (13 Apr, Shift 1)

Q4MHT CET 2026 · 13 APR · SHIFT 1Easy

Self-Inductance & Energy

The current flowing through the inductor of self inductance 'L' is continuously increasing at constant rate. The variation of induced e.m.f. (e) versus $\frac{dI}{dt}$ is shown graphically by figure

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Answer: (c)

$e = -L\frac{dI}{dt}$ : $e$ is directly proportional to $\frac{dI}{dt}$ with a negative constant $-L$ .
The graph is a straight line through the origin going into negative $e$ .
That is graph C, so the answer is (c).

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