The current gain in the common emitter mode of a transistor is 10. The input impedance is 20 kΩ and load resistance 100 kΩ. The power gain is (a) 300 (b) 500 (c) 200 (d) 100

Answer: (b). Voltage gain AV = β(RL)/(Ri) = 10 × 100/20 = 50 Power gain AP = β AV = 10 × 50 = 500 So the answer is (b) 500.

The current gain in the common emitter mode of a transistor is 10… | MHT CET 2026 (14 May, Shift 2)

Q6MHT CET 2026 · 14 MAY · SHIFT 2Easy

Junction Transistor

The current gain in the common emitter mode of a transistor is $10$ . The input impedance is $20\,k\Omega$ and load resistance $100\,k\Omega$ . The power gain is

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Answer: (b)

Voltage gain $A_V = \beta\frac{R_L}{R_i} = 10 \times \frac{100}{20} = 50$
Power gain $A_P = \beta A_V = 10 \times 50 = 500$
So the answer is (b) 500.

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