The current (I) drawn from the battery in the given circuit is (a) 0.2 A (b) 0.5 A (c) 0.6 A (d) 0.8 A

Answer: (b). Bridge A–B–C–D: RABRBD = 5/10 and RACRCD = 10/20, equal, so the bridge is balanced and the 10 Ω between B and C carries no current. Arm ABD: 5 + 10 = 15 Ω; arm ACD: 10 + 20 = 30 Ω. Req = (15 × 30)/(45) = 10 Ω I = 5/10 = 0.5 A. So the answer is (b) 0.5 A.

The current (I) drawn from the battery in the given circuit is | MHT CET 2025 (25 Apr, Shift 1)

Q14MHT CET 2025 · 25 APR · SHIFT 1Medium

Combination of Resistors

The current (I) drawn from the battery in the given circuit is

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Answer: (b)

Bridge A–B–C–D: $\dfrac{R_{AB}}{R_{BD}} = \dfrac{5}{10}$ and $\dfrac{R_{AC}}{R_{CD}} = \dfrac{10}{20}$ , equal, so the bridge is balanced and the $10\ \Omega$ between B and C carries no current.
Arm ABD: $5 + 10 = 15\ \Omega$ ; arm ACD: $10 + 20 = 30\ \Omega$ .
$R_{eq} = \dfrac{15 \times 30}{45} = 10\ \Omega$
$I = \dfrac{5}{10} = 0.5$ A. So the answer is (b) 0.5 A.

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