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NEET 1999 (AIPMT) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from NEET 1999 (AIPMT)

Q204NEET 1999 · AIPMTMedium

Kirchhoff's Laws & Measuring Instruments

The current (I)(I) in the given circuit is

Figure

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Answer: (b)

  1. The cell is across A and B: RA=3 ΩR_A = 3\ \Omega is in parallel with RB+RC=12 ΩR_B + R_C = 12\ \Omega.
  2. Req=3×123+12=2.4 ΩR_{eq} = \frac{3 \times 12}{3 + 12} = 2.4\ \Omega
  3. I=4.82.4=2I = \frac{4.8}{2.4} = 2 A
  4. So the answer is (b) 22 A.
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