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JEE Main 2020 (7 Jan, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2020 (7 Jan, Shift 1)

Q142JEE Main 2020 · 7 JAN · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

The current I1 (in A) flowing through 1 Ω\Omega resistor in the following circuit is:

Figure

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Answer: (c)

  1. The 2 Ω2\ \Omega (middle) is directly across the 11 V cell.
  2. Upper branch: (1∥1)+2=0.5+2=2.5 Ω(1 \parallel 1) + 2 = 0.5 + 2 = 2.5\ \Omega, so its current is 12.5=0.4\frac{1}{2.5} = 0.4 A.
  3. This splits equally in the two 1 Ω1\ \Omega resistors: I1=0.2I_1 = 0.2 A
  4. So the answer is (c) 0.2.
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