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MHT CET 2019 (2 May, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2019 (2 May, Shift 1)

Q156MHT CET 2019 · 2 MAY · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

The current in 1 Ω\Omega resistor in the following circuit is

Figure

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Answer: (a)

  1. 51=5010\frac{5}{1} = \frac{50}{10}, so the bridge is balanced and G carries no current.
  2. Upper path: 5+1=6 Ω5 + 1 = 6\ \Omega; lower path: 50+10=60 Ω50 + 10 = 60\ \Omega.
  3. I1Ω=1.1×6066=1I_{1\Omega} = 1.1 \times \frac{60}{66} = 1 A
  4. So the answer is (a) 1 A.
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