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JEE Main 2024 (1 Feb, Shift 1) · Electric Current, Drift Velocity & Current Density

Electric Current, Drift Velocity & Current Density question from JEE Main 2024 (1 Feb, Shift 1)

Q6JEE Main 2024 · 1 FEB · SHIFT 1Easy

Electric Current, Drift Velocity & Current Density

The current in a conductor is expressed as I=3t2+4t3I = 3t^{2} + 4t^{3}, where II is in Ampere and tt is in second. The amount of electric charge that flows through a section of the conductor during t=1 st = 1\text{ s} to t=2 st = 2\text{ s} is __________ C.

Numerical answer type. Work it out, then open the answer.

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Answer: 22

  1. q=∫12(3t2+4t3) dt=[t3+t4]12q = \int_1^2 (3t^{2} + 4t^{3})\,dt = \left[t^{3} + t^{4}\right]_1^2
  2. q=(8+16)−(1+1)q = (8 + 16) - (1 + 1)
  3. q=22 Cq = 22\text{ C}
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