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MHT CET 2024 (10 May, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2024 (10 May, Shift 1)

Q42MHT CET 2024 · 10 MAY · SHIFT 1Easy

Self-Inductance & Energy

The current in LR circuit if reduced to half What will be the energy stored in it?

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Answer: (d)

  1. U=12LI2∝I2U = \tfrac12 L I^2 \propto I^2.
  2. I′=I2⇒U′=U4I' = \dfrac{I}{2} \Rightarrow U' = \dfrac{U}{4}
  3. So the answer is (d) 14\tfrac14th times.
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