P-N Junction Diode question from NEET 2026

Answer: (d)

1. The left terminal of the battery is positive, so current flows left to right through the branches.
2. Diodes pointing right conduct: the $4\ \Omega$ and $2\ \Omega$ branches. Diodes pointing left block: the $3\ \Omega$ and $5\ \Omega$ branches.
3. $R_{eq} = \dfrac{4\times 2}{4 + 2} = \dfrac{4}{3}\ \Omega$
4. $I = \dfrac{10}{4/3} = \dfrac{15}{2}$ A
5. So the answer is (d) $\frac{15}{2}$ A.