The current in the following circuit is (a) 10 A (b) zero (c) 0.025 A (d) 10 ⁻² A

Answer: (d). The anode is at +5 V and the other end is at +3 V, so the diode is forward biased (ideal, zero drop). I = (5 - 3)/(200) = 2/200 = 10⁻² A So the answer is (d) 10⁻² A.

The current in the following circuit is | MHT CET 2021 (21 Sep, Shift 1)

Q74MHT CET 2021 · 21 SEP · SHIFT 1Medium

P-N Junction Diode

The current in the following circuit is

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Answer: (d)

The anode is at $+5$ V and the other end is at $+3$ V, so the diode is forward biased (ideal, zero drop).
$I = \dfrac{5 - 3}{200} = \dfrac{2}{200} = 10^{-2}$ A
So the answer is (d) $10^{-2}$ A.

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P-N Junction Diode question from MHT CET 2021 (21 Sep, Shift 1)

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