The current passing through the battery in the given circuit, is: (a) 2.5 A (b) 1.5 A (c) 2.0 A (d) 0.5 A

Answer: (d). C and D are joined by a wire, and so are A and F. The network between B and E is: B–A 5, B–D 2.5, A–E 3, D–E 1.5, A–D 6 Ω. 5/2.5 = 3/1.5, so the bridge is balanced and 6 Ω carries no current. RBE = ((5+3)(2.5+1.5))/(8 + 4) = 8/3 Ω Total = 8/3 + 1/3 + 5.5 + 1.5 = 10 Ω, so I = 5/10 So the answer is (d) 0.5 A.

The current passing through the battery in the given circuit, is: | NEET 2025

Q26NEET 2025Medium

Kirchhoff's Laws & Measuring Instruments

The current passing through the battery in the given circuit, is:

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Answer: (d)

C and D are joined by a wire, and so are A and F. The network between B and E is: B–A $5$ , B–D $2.5$ , A–E $3$ , D–E $1.5$ , A–D $6\ \Omega$ .
$\frac{5}{2.5} = \frac{3}{1.5}$ , so the bridge is balanced and $6\ \Omega$ carries no current.
$R_{BE} = \frac{(5+3)(2.5+1.5)}{8 + 4} = \frac{8}{3}\ \Omega$
Total $= \frac{8}{3} + \frac{1}{3} + 5.5 + 1.5 = 10\ \Omega$ , so $I = \frac{5}{10}$
So the answer is (d) 0.5 A.

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