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MHT CET 2026 (17 Apr, Shift 2) · Moving Coil Galvanometer, Ammeter & Voltmeter

Moving Coil Galvanometer, Ammeter & Voltmeter question from MHT CET 2026 (17 Apr, Shift 2)

Q4MHT CET 2026 · 17 APR · SHIFT 2Easy

Moving Coil Galvanometer, Ammeter & Voltmeter

The current passing through the galvanometer is 4 % of the total current in the curcuit. If the resistance of the galvanometer is 'G', the shunt resistance 'S' connected across the galvanometer is

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Answer: (c)

$I_gG = (I - I_g)S$ with $I_g = 0.04I$ .
$S = \frac{0.04G}{0.96} = \frac{G}{24}$
So the answer is (c) $\frac{G}{24}$ .

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