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JEE Main 2023 (10 Apr, Shift 1) · Hysteresis, Soft Iron vs Steel & Shielding

Hysteresis, Soft Iron vs Steel & Shielding question from JEE Main 2023 (10 Apr, Shift 1)

Q7JEE Main 2023 · 10 APR · SHIFT 1Easy

Hysteresis, Soft Iron vs Steel & Shielding

The current required to be passed through a solenoid of 15 cm length and 60 turns in order of demagnetise a bar magnet of magnetic intensity $2.4 \times 10^{3}\text{ Am}^{-1}$ is ___________ A.

Numerical answer type. Work it out, then open the answer.

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Answer: 6

The solenoid's $H = nI$ must equal the given magnetic intensity (the coercivity): $I = \dfrac{H}{n}$ .
$n = \dfrac{60}{0.15} = 400\text{ m}^{-1}$
$I = \dfrac{2.4 \times 10^{3}}{400} = 6\text{ A}$
So the answer is 6 A.

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