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MHT CET 2026 (19 May, Shift 2) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2026 (19 May, Shift 2)

Q2MHT CET 2026 · 19 MAY · SHIFT 2Easy

Force on Current-Carrying Conductors

The currents through two thin long parallel wires, A and B carrying $I$ and $\frac{I}{3}$ respectively, in the same direction. The distance between two wires is ' $d$ '. The magnitude of force per unit length exerted by wire A on wire B is

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Answer: (a)

Force per unit length between parallel wires: $\dfrac{F}{L} = \dfrac{\mu_0 I_1 I_2}{2\pi d}$ .
$\dfrac{F}{L} = \dfrac{\mu_0 I (I/3)}{2\pi d} = \dfrac{\mu_0 I^2}{6\pi d}$
So the answer is (a).

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